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Show the f(x) \(= \frac{x^2 + x - 6}{x^2 - 4}\) , \(x \neq 2\) has a continuous extension to \(x = 2\) .

BIT Basic Mathematics · 2077 · Solved Question with Answer

Show the f(x) \(= \frac{x^2 + x - 6}{x^2 - 4}\), \(x \neq 2\) has a continuous extension to \(x = 2\).

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