(a) हल गर्नुहोस् । (Solve): \(\dfrac{p}{x-y} -… – SEE Class 10 Compulsory Maths 2082 Solved

SEE Class 10 Compulsory Maths · 2082 · Solved Question with Answer

(a) हल गर्नुहोस् । (Solve): \(\dfrac{p}{x-y} - \dfrac{p}{x+y}\)

(b) सरल गर्नुहोस् । (Simplify): \(2^x + 2^{-x} - 1 = \dfrac{3}{2}\)

Solution

(a) हल गर्नुहोस् । (Solve): \(\dfrac{p}{x-y} - \dfrac{p}{x+y}\) (b) सरल गर्नुहोस् । (Simplify): \(2^x + 2^{-x} - 1 = \dfrac{3}{2}\)