a) सरल गर्नुहोस (Simplify): \(\frac{1}{x - y} - \frac{y}{xy + y^2}\) b) यदि \(x = 2^{\left(\frac{1}{3}\right)} - 2^{\left(-\frac{1}{3}\right)}\) भए…
SEE Class 10 Compulsory Maths · 2080 · Solved Question with Answer
a) सरल गर्नुहोस (Simplify): \(\frac{1}{x - y} - \frac{y}{xy + y^2}\)
b) यदि \(x = 2^{\left(\frac{1}{3}\right)} - 2^{\left(-\frac{1}{3}\right)}\) भए प्रमाणित गर्नुहोस् : \(2x^3 + 6x - 3 = 0\)
If \(x = 2^{\left(\frac{1}{3}\right)} - 2^{\left(-\frac{1}{3}\right)}\) , prove that: \(2x^3 + 6x - 3 = 0\)