(a) सरल गर्नुहोस् । (Simplify): \(\frac{1}{x-y} -… – SEE Class 10 Compulsory Maths 2082 Solved

SEE Class 10 Compulsory Maths · 2082 · Solved Question with Answer

(a) सरल गर्नुहोस् । (Simplify): \(\frac{1}{x-y} - \frac{x+y}{x^2-y^2}\)

(b) हल गर्नुहोस् । (Solve): \(25^x - 6 \times 5^{x+1} + 125 = 0\)

Solution

(a) सरल गर्नुहोस् । (Simplify): \(\frac{1}{x-y} - \frac{x+y}{x^2-y^2}\) (b) हल गर्नुहोस् । (Solve): \(25^x - 6 \times 5^{x+1} + 125 = 0\)