(a) सरल गर्नुहोस् । (Simplify): \(\frac{1}{1+a^{-1}} +… – SEE Class 10 Compulsory Maths 2082 Solved

SEE Class 10 Compulsory Maths · 2082 · Solved Question with Answer

(a) सरल गर्नुहोस् । (Simplify): \(\frac{1}{1+a^{-1}} + \frac{1}{1-a^{-1}}\)

(b) हल गर्नुहोस् । (Solve): \(2^{2x} - 3 \cdot 2^{x+1} + 8 = 0\)

Solution

(a) सरल गर्नुहोस् । (Simplify): \(\frac{1}{1+a^{-1}} + \frac{1}{1-a^{-1}}\) (b) हल गर्नुहोस् । (Solve): \(2^{2x} - 3 \cdot 2^{x+1} + 8 = 0\)