A function \(f(x)\) is defined by \(f(x) = \begin{cases} \frac{2x^2-18}{x-3} & \text{for } x \ne 3 \\ k & \text{for } x = 3 \end{cases}\) Find the…
bitm Basic Mathematics · 2024 · Solved Question with Answer
A function \(f(x)\) is defined by \(f(x) = \begin{cases} \frac{2x^2-18}{x-3} & \text{for } x \ne 3 \\ k & \text{for } x = 3 \end{cases}\)
Find the value of k so that \(f(x)\) is continuous at \(x = 3\)